mac_5x9x8-Revised.md

@@ -87,6 +87,12 @@ p4_3[4:0] = a4[4:0] * b4[3]
     P[11]  P[10]  P[9]    P[8]   P[7]      P[6]      P[5]      P[4]      P[3]      P[2]      P[1]      P[0]
 ```
 
+
+
+
+
+... This is wrong below
+
 Focusing on the upper 4 high bits of these 5 constant terms, if K is even, these will always sum to zeroes and a carry out bit, have no effect on the result, and can be replaced with zeroes. If K is odd, these will always sum to 1's, inverting the upper 4 bits of the output sum. Therefore, those can be replaced with zeroes and inverting the upper 4 bits of P (`P[11:8]`) after summation.
 
 The column of bits at `(1 << (M-1))` can be summed together prior to compilation into one constant value of `(K << (M-1))`. Therefore, the final MAC output can be shown by: